-16x-64-x^2=0

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Solution for -16x-64-x^2=0 equation: 



-16x-64-x^2=0

We add all the numbers together, and all the variables

-1x^2-16x-64=0

a = -1; b = -16; c = -64;
Δ = b2-4ac
Δ = -162-4·(-1)·(-64)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{-2}=-8$

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